On Jun 1, 2010, at 12:20 PM, Aaron D. Ball wrote:
The underlying object here is a Unix file descriptor, which is just a number. In that sense, stdin is 0, stdout is 1, and stderr is 2, so this would be (0 + 2) (mod 1) = 0
Every integer is 0 (mod 1). _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
