John Lato schrieb:
> Hello,
>
> I was wondering today, is this generally true?
>
> instance (Monad m, Monoid a) => Monoid (m a) where
> mempty = return mempty
> mappend = liftM2 mappend
>
> I know it isn't a good idea to use this instance, but assuming that
> the instance head does what I mean, is it valid? Or more generally is
> it true for applicative functors as well? I think it works for a few
> tricky monads, but that's not any sort of proof. I don't even know
> how to express what would need to be proven here.
I translate 'valid' and 'true' to "Is 'm a' a Monoid, given that 'm' is
a Monad and 'a' is a Monoid?" If this is the question then we have to
show the Monoid laws for (m a), namely
left identity: forall x. mappend mempty x = x
right identity: forall x. mappend x mempty = x
associativity:
forall x y z.
(x `mappend` y) `mappend` z = x `mappend` (y `mappend` z)
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