Hi, Ryan and all,
Bingo! I guess my question was all right after all.
I tried creating an instance earlier but
*Main> :t (->) Int Char
<interactive>:1:1: parse error on input `->'
What got loaded with FmapFunc? I Hoogled it and got back nothing.
Michael
--- On Tue, 8/31/10, Ryan Ingram <ryani.s...@gmail.com> wrote:
From: Ryan Ingram <ryani.s...@gmail.com>
Subject: Re: [Haskell-cafe] On to applicative
To: "michael rice" <nowg...@yahoo.com>
Cc: "Vo Minh Thu" <not...@gmail.com>, haskell-cafe@haskell.org
Date: Tuesday, August 31, 2010, 2:36 PM
Prelude FmapFunc> let s = show :: ((->) Int) String
Prelude FmapFunc> :t s
s :: Int -> String
Prelude FmapFunc> let v = fmap ("hello " ++) s
Prelude FmapFunc> :t v
v :: Int -> String
Prelude FmapFunc> v 1
"hello 1"
-- ryan
On Tue, Aug 31, 2010 at 11:28 AM, michael rice <nowg...@yahoo.com> wrote:
I'm not sure if my terminology is correct or even if my question makes sense,
but I can create "instances" of Maybe, List, IO, and Either.
Prelude Data.Either> let m = Just 7
Prelude Data.Either> :t m
m :: Maybe Integer
Prelude Data.Either> let l = 2:[]
Prelude Data.Either> :t l
l :: [Integer]
Prelude Data.Either> let g = getLine
Prelude Data.Either> :t g
g :: IO String
Prelude Data.Either> let e = Right "abc"
Prelude Data.Either> :t e
e :: Either a [Char]
All these instances are functors, each with its own version of fmap that can be
applied to it.
How can I similarly create an instance of (->) so I can apply (->)'s version of
fmap
instance Functor ((->) r) where
fmap f g = (\x -> f (g x))
to
it?
Michael
--- On Tue, 8/31/10, Vo Minh Thu <not...@gmail.com> wrote:
From: Vo Minh Thu <not...@gmail.com>
Subject: Re: [Haskell-cafe] On to applicative
To: "michael rice" <nowg...@yahoo.com>
Cc: haskell-cafe@haskell.org
Date: Tuesday, August 31, 2010, 1:50 PM
2010/8/31 michael rice <nowg...@yahoo.com>
>
> So it's a type constructor, not a type? Could you please provide a simple
> example of its usage?
Sure, although I'm sure you've come by some already.
-- the identity function
id :: a -> a
-- often, we write it like this:
-- id x = x
-- but here we see the relationship between the ananymous function
syntax and the function
type:
id = \x -> x
In fact, if you write in prefix form, it is quite familiar:
f :: (->) Int Bool
e = Either String Float
Cheers,
Thu
> Michael
>
> --- On Tue, 8/31/10, Vo Minh Thu <not...@gmail.com> wrote:
>
> From: Vo Minh Thu <not...@gmail.com>
> Subject: Re: [Haskell-cafe] On to applicative
> To: "michael rice" <nowg...@yahoo.com>
> Cc: haskell-cafe@haskell.org
> Date: Tuesday, August 31, 2010, 1:17 PM
>
> 2010/8/31 michael rice <nowg...@yahoo.com>
> >
> > "Learn You a Haskell ..." says that (->) is a type just like Either. Where
> > can I find its type definition?
>
> You can't define it *in* Haskell as user code. It is a built-in infix
> type constructor (Either or Maybe are type constructors too, not just
> types). In fact, if you want to implement a simple, typed functional
> language, you'll find it is the only built-in type constructor you
> have to implement (as the implementor of the language).
>
> Also,
> Show a => a
> is a type too, but you won't find a definition for 'a' or for '=>'.
> All those things are defined by the language.
>
> Cheers,
> Thu
>
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