On 27/09/2010, at 5:20 AM, rgowka1 wrote: > Type signature would be Int -> [Double] -> [(Double,Double)] > > Any thoughts or ideas on how to calculate a n-element moving average > of a list of Doubles? > > Let's say [1..10]::[Double] > > what is the function to calculate the average of the 3 elements? > > [(1,0),(2,0),(3,2),(4,3)....] :: [(Double,Double)]
> moving_average3 (xs0 @ (_ : (xs1 @ (_ : xs2)))) = > zipWith3 (\x y z -> (x+y+z)/3) xs0 xs1 xs2 *Main> moving_average3 [1..10] [2.0,3.0,4.0,5.0,6.0,7.0,8.0,9.0] The result is two elements shorter than the original, but that _is_ the definition of moving average after all. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe