I read the parsec documentation and saw my mistake. By the way, there is a parser that returns [String] for my case? -- View this message in context: http://haskell.1045720.n5.nabble.com/Haskell-Helper-tp3093854p3198573.html Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
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