On Thu, Nov 04, 2010 at 05:38:12PM +0000, Simon Peyton-Jones wrote: > > The generator uses crypto functions,
Does that mean it couldn't be used in some countries? > so it's probably more computationally expensive than common linear-sequence > generators, but in exchange you get robust splitting. I wonder if you can make a splittable generator that uses crypto functions when you split it, but is a common linear-sequence generator otherwise? Thanks Ian _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
