On Fri, Dec 17, 2010 at 11:04 AM, michael rice <nowg...@yahoo.com> wrote:
> I don't understand this error message. Haskell appears not to understand > that 1 is a Num. > > Prelude> :t 1 > 1 :: (Num t) => t > Prelude> :t [1,2,3,4,5] > [1,2,3,4,5] :: (Num t) => [t] > Prelude> > > Michael > > =================== > > f :: [Int] -> IO [Int] > f lst = do return lst > > main = do let lst = f [1,2,3,4,5] > fmap (+1) lst > > =============================== > > Prelude> :l test > [1 of 1] Compiling Main ( test.hs, interpreted ) > > test.hs:5:17: > No instance for (Num [Int]) > arising from the literal `1' at test.hs:5:17 > Possible fix: add an instance declaration for (Num [Int]) > In the second argument of `(+)', namely `1' > In the first argument of `fmap', namely `(+ 1)' > In the expression: fmap (+ 1) lst > Failed, modules loaded: none. > Prelude> > > > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe > > Excuse any inaccuracies, I'm somewhat new at Haskell myself, but what it looks like is happening is that at the point in main where you've bound "lst", it will have type of "IO [Int]". The signature for fmap is: fmap :: (Functor f) => (a -> b) -> f a -> f b if you call fmap (+1) the next argument that fmap "expects" is something that is "in" just one functor, for example, this fmap (+1) [1,2,3,4,5] works fine, but, something that is "IO [Int]" won't. You can compose two 'fmap's to solve this: :t (fmap.fmap) (fmap.fmap) :: (Functor f, Functor f1) => (a -> b) -> f (f1 a) -> f (f1 b) which means that 'main' looks like: main = do let lst = f [1, 2, 3, 4, 5] (fmap.fmap) (+1) lst -- Chris Wilson <christopher.j.wil...@gmail.com>
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