What about having the order by diagonals, like:
0 1 3
2 4
5
and have none of the pair be bounded?
--
Markus Läll
On 4 Mar 2011, at 01:10, Daniel Fischer <daniel.is.fisc...@googlemail.com
> wrote:
On Thursday 03 March 2011 23:25:48, Alexander Solla wrote:
On Thu, Mar 3, 2011 at 1:58 PM, Richard O'Keefe <o...@cs.otago.ac.nz>
wrote:
I can't think of an approach that doesn't require all but one of
the tuple elements to have Bounded types.
It's not possible.
Meaning: It's not possible while respecting the order.
Ignoring the order, it's of course possible (finite products of
countable
sets are countable).
_______________________________________________
Haskell-Cafe mailing list
Haskell-Cafe@haskell.org
http://www.haskell.org/mailman/listinfo/haskell-cafe
_______________________________________________
Haskell-Cafe mailing list
Haskell-Cafe@haskell.org
http://www.haskell.org/mailman/listinfo/haskell-cafe