Magnifique, ca marche! Grand merci, Vincent! On Wed, Jun 15, 2011 at 1:16 AM, Vincent Gerard <vinc...@xenbox.fr> wrote:
> Hello Dmitri, > > It seems that your format pattern does not match exactly the format of > the input, thus the parser returns Nothing. > > Try the following format string which seems to work with your date: > > parseTime defaultTimeLocale "%m/%d/%Y %l:%M:%S %p" ds :: Maybe > UTCTime returns : Just 2009-10-11 19:04:28 UTC > > The parsings errors in your format could come from > . %D expects a 2 char year > . %H expects a 0 padded hour (like 07, not 7) > > Regards, > > Vincent Gerard > > On Wed, 15 Jun 2011 00:33:56 +0400 > "Dmitri O.Kondratiev" <doko...@gmail.com> wrote: > > > I am trying to convert data string to time: > > > > import Data.Time > > import Data.Time.Format > > import Locale > > > > ds = "10/11/2009 7:04:28 PM" > > t = parseTime defaultTimeLocale "%D %H:%M:%S %p" ds :: Maybe UTCTime > > > > and get "Nothing". > > What is wrong? > > > > Thanks ! > > Dmitri. > >
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