Hello, quick question about unboxed Vectors :
Is it possible to create an unboxed vector of unboxed vector ? : > import qualified Data.Vector.Unboxed as V > type UnboxedNestedVextor = V.Vector (V.Vector Int) Alternatively I would have to use: > import qualified Data.Vector.Unboxed as V > import qualified Data.Vector as VB type UnboxedNestedVextor = VB.Vector (V.Vector Int) Is there a rule of thumb how much quicker Unboxed Vectors are ? Cheers Phil -- View this message in context: http://haskell.1045720.n5.nabble.com/Data-Vector-Unboxed-tp4977289p4977289.html Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
