2011/11/7 José Pedro Magalhães <j...@cs.uu.nl>: > Hi, > I'm not sure I understand your question. But if you mean that you want to > retrieve the type variable names, as they were defined in the source, then I > can tell you that the generic deriving mechanism cannot do this. > > Cheers, > Pedro > > On Sun, Nov 6, 2011 at 14:35, Magicloud Magiclouds > <magicloud.magiclo...@gmail.com> wrote: >> >> Hi, >> I'd like to simpler the work of deriving MyClass. And I have two >> ways to do: TemplateHaskell "$(derivingMyClass)", or Generic "deriving >> (MyClass)". >> Since I need to get the type name in the deriving, then I met this >> question: If I have "data A b = C b", then with TemplateHaskell, the >> type would be "VarT b", which means at compile time, I cannot get the >> exact type, so the type name would be "b". >> So I wonder if this could be resolved by TemplateHaskell, or Generic >> is the only choice. >> >> PS: I have not tried to do this in Generic. >> -- >> 竹密岂妨流水过 >> 山高哪阻野云飞 >> >> _______________________________________________ >> Haskell-Cafe mailing list >> Haskell-Cafe@haskell.org >> http://www.haskell.org/mailman/listinfo/haskell-cafe > >
Thank you. After deeply thinking about this, GH sure does not.... -- 竹密岂妨流水过 山高哪阻野云飞 _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
