Hey all, Can GHC eliminate one of two equal ByteStrings, when they are compared and turns out to be equal?
Say i have a map, ByteString -> Int. I now do a lookup on a ByteString and if it exists, I insert this ByteString into a list. Is it possible to avoid using more memory, than used by the keys in the map + the list structure? I.e. is it possible to eliminate the redundant ByteStrings somehow? I guess, this could be done by having lookup return the key as well, and then insert this key into the list, however, that's a bit ugly and somewhat anti-intuitive. Here's an example program, to illustrate the idea: https://gist.github.com/1472418 -- Johan Brinch _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe