If you're interested in learning parsec, RWH covered this topic in depth in
Chapter 16, Choices and Errors:
http://book.realworldhaskell.org/read/using-parsec.html.

On Mon, Jan 2, 2012 at 3:44 AM, max <m...@mtw.ru> wrote:

> I want to write a function whose behavior is as follows:
>
> foo "string1\nstring2\r\nstring3\nstring4" = ["string1",
> "string2\r\nstring3", "string4"]
>
> Note the sequence "\r\n", which is ignored. How can I do this?
>
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