On Thu, May 31, 2012 at 6:35 PM, Clark Gaebel wrote: > *X> 3^40 `mod` 3 == modexp2 3 40 3 > False > *X> modexp2 3 40 3 > 0 > *X> 3^40 `mod` 3 > 0 >
*X> 3^40 `mod` 3 :: Int 1 *X> 3^40 `mod` 3 :: Integer 0 I'm confused. Last I checked, 0 == 0. > Yes, but 3^40 /= 3^40 when you have arithmetic overflow: *X> 3^40 :: Int 689956897 *X> 3^40 :: Integer 12157665459056928801 Regards, Sean
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