John Meacham wrote:
On Thu, Mar 02, 2006 at 03:53:45AM -0000, Claus Reinke wrote:
the problem is that we have somehow conjured up an infinite
type for Mul to recurse on without end! Normally, such infinite
types are ruled out by occurs-checks (unless you are working
with Prolog III;-), so someone forgot to do that here. why?
where? how?
Polymorphic recursion allows the construction of infinite types if I
understand what you mean.
No, that's different. An infinite type can't be written in (legal) Haskell.
It's something like
type T = [T]
-- Ben
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