Hello Iavor, Thursday, October 26, 2006, 4:51:00 AM, you wrote:
> kb,mg,gb :: Num a => a > kb = 1024 > mb = 1024 * kb > gb = 1024 * mb b :kb :mb :gb :_ = iterate (1024*) 1 :: [Int] b_:kb_:mb_:gb_:tb_:_ = iterate (1024*) 1 :: [Integer] > and now we can write (4 * kb) instead for 4096. btw, your variant requires re-calculating values on each their use -- Best regards, Bulat mailto:[EMAIL PROTECTED] _______________________________________________ Haskell-prime mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-prime
