Should the following be legal or not? data T a = F (a->a->Bool) x = F (==) The compilers all produce an `ambiguous overloading' error, and I am not sure why. Everything is OK if you give a type declaration for x (x :: Eq a => T a) or if you add an argument to x. Ian [EMAIL PROTECTED], Tel: 0272 303334
- Overloading ian
- Overloading jcp
- Overloading Carlos Camarao de Figueiredo
- Re: Overloading Carlos Camar�o
