>>>>> "Fergus" == Fergus Henderson <[EMAIL PROTECTED]> writes:
Fergus> Basically there is no way to do this in Haskell. About the
Fergus> best you can do is to create your own `EqMonad' class, which is
Fergus> like `Monad' except that it has an `Eq a' constraint on the
Fergus> type variable. Then use `EqMonad' instead of `Monad'. You
Fergus> can't use the `do' syntax, and you can't reuse the library
Fergus> routines that work on Monads.
Ok, thanks, I can redo the do. But this does strike me as a flaw in the
language. What would the ramifications be for an accomodation as such? Surely
not so drastic as the dependent type thingy.
cheers,
kirstin
--
Don't worry -- the brontosaurus is slow, stupid, and placid.
