I'm not sure exactly what you mean. Say I have something like that, then what's the difference between saying:
f = do { action1; action2; action3 } and simply f = do action3 ? If the result of each of the actions is ignored for the following ones, why do we need to do this monadically? -- Hal Daume III "Computer science is no more about computers | [EMAIL PROTECTED] than astronomy is about telescopes." -Dijkstra | www.isi.edu/~hdaume On Mon, 18 Feb 2002, Andre W B Furtado wrote: > Roughly speaking, I'm in need of a monad (say MyIO) that interprets the > following code > > >f :: MyIO () > >f = do > > action1 > > action2 > > action3 > > ... > > return () > > > as applying action1 to g, then action2 to the SAME g (not the result of > action1) and so on... > > Of course, this "g" will be specified when starting the monad (something > like "runMyIO g"). Does this "composition monad" already exist? If no, can > anyone give me some hints to create my own? > > Thanks a lot > -- Andre > > _______________________________________________ > Haskell mailing list > [EMAIL PROTECTED] > http://www.haskell.org/mailman/listinfo/haskell > _______________________________________________ Haskell mailing list [EMAIL PROTECTED] http://www.haskell.org/mailman/listinfo/haskell