Hi,
Tks, this is not what I wanted.
I want remove pairs list,
[(5,1),(4,1),(3,1),(2,1),(1,1)] remove [(2,1),(1,1)]
[(5,1),(4,1),(3,1)]
so pairs [(2,1),(1,1)] removed.
Tks.
--- Pierre Barbier de Reuille
<[EMAIL PROTECTED]> wrote:
> One answer is the infix operator (\\) defined in the
> List module (or in
> Data.List ...)
>
> But it's in ont of the "set" operations. For example
> try :
>
> [1..10] \\ [3..6]
> [1,2,7,8,9,10]
>
> But also :
>
> ([1..10]++[1..10]) \\ [3..6]
> [1,2,7,8,9,10,1,2,7,8,9,10]
>
> So _all_ the elements with values in [3..6] where
> removed !!
> If that's what you want ! Perfect ... if not : what
> do you want exactly
> ? List substraction is not uniq.
>
> Pierre
>
> Bright Sun a �crit :
> > In Haskell, ++ can spends second list argument
> onto
> > the end of first list argument.� How to substract
> the
> > second list from the first list?
> >
> > For example,
> > [(5,1),(4,1),(3,1),(2,1),(1,1)]
> > substract
> > [(2,1),(1,1)]
> > I want to get result list:
> > [(5,1),(4,1),(3,1)]
> >
> > Tks.�
> >
> >
> > ��� �������
> > __________________________________
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> >
>
> --
> Pierre Barbier de Reuille
>
> INRA - UMR Cirad/Inra/Cnrs/Univ.MontpellierII AMAP
> Botanique et Bio-informatique de l'Architecture des
> Plantes
> TA40/PSII, Boulevard de la Lironde
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>
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