Ben Lippmeier <[EMAIL PROTECTED]> writes: > To gloss over details: it'll reduce x far enough so it knows that it's > an Integer, but it won't nessesarally compute that integers value.
No, Integers don't contain any lazy components. It statically knows that it's an integer. -- __("< Marcin Kowalczyk \__/ [EMAIL PROTECTED] ^^ http://qrnik.knm.org.pl/~qrczak/ _______________________________________________ Haskell mailing list Haskell@haskell.org http://www.haskell.org/mailman/listinfo/haskell