Help! One of two things is going on:

1) I don't understand what I'm doing
2) GHC is inferring different types for pointed and
   point-free function definition.

I wanted to define Haskell equivalents to the C ternary operator.
Basically, predicate ??? doIfTrue ||| doIfFalse

For some reason, though, in GHC 6.4 and 6.7, the types
inferred for abs1 and ab2 (defined below) are different:

*Main> :t abs1
abs1 :: (Num a, Ord a) => a -> a

*Main> :t abs2
abs2 :: Integer -> Integer

How is abs2 less general just because I use point-free
notation instead of pointed notation? They should have the same
type, no?  I'm stumped...

> import Control.Arrow
> import Data.Either
>
> infix 1 ?, ??, ???, ????
>
> (?)  True  = Left
> (?)  False = Right
>
> (??) True  = Left  . fst
> (??) False = Right . snd
>
> p ???  q = (p &&& arr id) >>> uncurry (?)  >>> q
> p ???? q = (p &&& arr id) >>> uncurry (??) >>> q
>
> abs1 x = (< 0) ??? negate ||| id $ x
> abs2   = (< 0) ??? negate ||| id
>
> checks :: [Bool]
> checks =
>  [
>   (True   ?                              3 ) == (Left   3),
>   (False  ?                              4 ) == (Right  4),
>   (True  ??                           (3,4)) == (Left   3),
>   (False ??                           (3,4)) == (Right  4),
>   (even ??? (`div` 2) ||| (+1).(*3) $  3   ) == (      10),
>   (even ??? (`div` 2) ||| (+1).(*3) $    4 ) == (       2),
>   (uncurry (==) ????  (+1) ||| (*3) $ (3,3)) == (       4),
>   (uncurry (==) ????  (+1) ||| (*3) $ (3,4)) == (      12),
>   (uncurry (==) ????  (+1) +++ (*3) $ (3,3)) == (Left   4),
>   (uncurry (==) ????  (+1) +++ (*3) $ (3,4)) == (Right 12),
>   (abs1   5                                ) == (       5),
>   (abs1 (-5)                               ) == (       5),
>   (abs2   5                                ) == (       5),
>   (abs2 (-5)                               ) == (       5)
>  ]
>
> main = print (and checks)

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