On Tue, Jan 12, 2010 at 9:32 PM, Something Something < [email protected]> wrote:
> Thanks for the explanation. So as per the link you provided the list() > method would return a sorted list, correct? > > Thats what it says in the javadoc. > About the 2nd point, I am using result.getFamilyMap() which returns > NavigableMap which extends SortedMap (as per > > http://java.sun.com/javase/6/docs/api/java/util/NavigableMap.html?is-external=true > ), > so I guess the returned Map would be sorted by key values, so I am safe > there as well, correct? > Yes. That sounds right. The raw method is there so applications that can deal, can get the raw results without client machinations getting in the way. St.Ack > > > On Tue, Jan 12, 2010 at 4:46 PM, stack <[email protected]> wrote: > > > On Tue, Jan 12, 2010 at 2:01 PM, Something Something < > > [email protected]> wrote: > > > > > All the Keys returned by this code are guaranteed to be in order by the > > key > > > values, correct? > > > > > > > No. Explicitly, the order is NOT guaranteed, for performance reasons (I > > don't see this in the javadoc. It should be there). If just getting > > latest > > version from a set of columns, I believe it will come across in the right > > order but not guaranteed. To get a guaranteed sorted order, call > > > > > http://hadoop.apache.org/hbase/docs/current/api/org/apache/hadoop/hbase/client/Result.html#sorted()instead > < > http://hadoop.apache.org/hbase/docs/current/api/org/apache/hadoop/hbase/client/Result.html#sorted%28%29instead > > > > of the raw() method. The sort will be done client-side. > > > > > > > > > > Also, for some other table I am retrieving all column names for a > > > particular > > > key, and those all seem to be in the correct order as well. Is this > > always > > > guaranteed? > > > > > > > Call sort if you need guarantee. > > > > St.Ack > > > > > > > > > > > > > > > > > > > > On Tue, Jan 12, 2010 at 11:12 AM, stack <[email protected]> wrote: > > > > > > > Setup the scanner and next it as you did previous. Then on the > Result > > > > object, do something like: > > > > > > > > for (KeyValue kv: result.raw()) { > > > > System.out.println(Bytes.toString(kv.getRow()) + " " + > > > > Bytes.toString(kv.getValue())); > > > > } > > > > > > > > St.Ack > > > > > > > > On Tue, Jan 12, 2010 at 10:24 AM, Something Something < > > > > [email protected]> wrote: > > > > > > > > > Sorry. That was a typo. In any case, it seems like I am using the > > > wrong > > > > > API. > > > > > > > > > > Here's what my table contains: > > > > > > > > > > > > > > > ABC_111 column=info:estimate, > > > > timestamp=1263319888463, > > > > > value=179.59 > > > > > ABC_222 column=info:estimate, > > > > timestamp=1263319888463, > > > > > value=191.50 > > > > > ABC_333 column=info:estimate, > > > > timestamp=1263319888463, > > > > > value=180.65 > > > > > ABC_444 column=info:estimate, > > > > timestamp=1263319888463, > > > > > value=183.63 > > > > > & so on.... > > > > > > > > > > > > > > > I want to retrieve: > > > > > > > > > > ABC_111 179.59 > > > > > ABC_222 191.50 > > > > > ABC_333 180.65 > > > > > ABC_444 183.63 > > > > > & so on... > > > > > > > > > > What API should I use? Please let me know. Thanks for your help. > > > > > > > > > > > > > > > On Tue, Jan 12, 2010 at 9:36 AM, stack <[email protected]> wrote: > > > > > > > > > > > See below: > > > > > > > > > > > > On Tue, Jan 12, 2010 at 9:12 AM, Something Something < > > > > > > [email protected]> wrote: > > > > > > > > > > > > > > NavigableMap<byte[], NavigableMap<byte[], > > > > NavigableMap<Long, > > > > > > > byte[]>>> map = result.getMap(); > > > > > > > > > > > > > > > > > > > Above returns a map keyed by families: > > > > > > > > > > > > > > > > > > > > > > > > > > > http://hadoop.apache.org/hbase/docs/current/api/org/apache/hadoop/hbase/client/Result.html#getMap%28%29 > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > for (Map.Entry<byte[], NavigableMap<byte[], > > > > > NavigableMap<Long, > > > > > > > byte[]>>> entry : map.entrySet()) { > > > > > > > byte[] key = entry.getKey(); > > > > > > > > > > > > > > > > > > > This is family name, not key. > > > > > > > > > > > > > > > > > > > > > > > > > *LOG.info("key = " + Bytes.toString(key));* > > > > > > > NavigableMap<byte[], NavigableMap<Long, byte[]>> > value > > = > > > > > > > entry.getValue(); > > > > > > > > > > > > > > > > > > > This is a map keyed by column qualifiers. > > > > > > > > > > > > > > > > > > > > > > > > > for (Entry<byte[], NavigableMap<Long, byte[]>> > > entry1 > > > : > > > > > > > value.entrySet()) { > > > > > > > byte[] key1 = entry1.getKey(); > > > > > > > *LOG.info("key1 = " + Bytes.toString(key1));* > > > > > > > > > > > > > > > > > > > > > > > > > This is the family qualifier. > > > > > > > > > > > > > > > > > > > > > > > > > NavigableMap<byte[], NavigableMap<Long, > byte[]>> > > > > > value1 > > > > > > = > > > > > > > entry.getValue(); > > > > > > > > > > > > > > > > > > > > > > > > > I do not think you intended to do this. I think you meant > entry1, > > > not > > > > > > 'entry' and map type should be NavigableMap<Long, byte[]> rather > > than > > > > > > above. > > > > > > > > > > > > St.Ack > > > > > > > > > > > > > > > > > > > > > > > > > for (Entry<byte[], NavigableMap<Long, byte[]>> > > > > entry2 > > > > > : > > > > > > > value1.entrySet()) { > > > > > > > String key2 = > > Bytes.toString(entry2.getKey()); > > > > > > > *LOG.info("key2 = " + key2);* > > > > > > > > > > > > > > } > > > > > > > } > > > > > > > } > > > > > > > } > > > > > > > > > > > > > > > > > > > > > > > > > > > >
