Sorry about the confusion I brought up. I got this wrong information from
the manufacturer. If I recall my previous experience, Sigma f/3.5 matches
Radiance -vta pretty well. The current mismatch might be caused by the
camera coordinate in the simulation.
Anyway, Happy Chinese New Year, everyone!


Zhe



On Fri, Jan 27, 2017 at 10:11 AM, <[email protected]> wrote:

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>    1. Re: Convert equisolidangular to equiangular projection
>       (Gregory J. Ward)
>
>
> ----------------------------------------------------------------------
>
> Message: 1
> Date: Fri, 27 Jan 2017 08:10:53 -0800
> From: "Gregory J. Ward" <[email protected]>
> To: High Dynamic Range Imaging <[email protected]>
> Subject: Re: [HDRI] Convert equisolidangular to equiangular projection
> Message-ID: <[email protected]>
> Content-Type: text/plain; charset="windows-1252"
>
> Raquel points out an important error in this discussion's terminology.
> The "equidistant" fisheye does indeed correspond to the "-vta" view type in
> Radiance.  However, the "-vth" type corresponds to a hemispherical
> projection, which very few commercial fisheye lenses realize.  In
> particular, the equisolidangle projection is much closer to "-vta" than it
> is to "-vth".  If your lens is equisolidangle, then you need to use the
> fisheye_corr.cal script or similar to convert it to an equidistant
> projection.
>
> I have not implemented the equisolidangle projection, though there is a
> third fisheye type (-vts) which is called "stereographic", although we
> prefer the term "planisphere" projection to avoid confusion with stereo
> views.  This does not correspond to any commercial lenses to my knowledge,
> but I'd be interested to hear of one.
>
> > From: Raquel Viula <[email protected]>
> > Date: January 27, 2017 5:49:57 AM PST
> >
> > Hi all,
> > Thank you for raising this topic and sharing your views. I?m using the
> output of a Sigma f=4.5mm F/2.8 for several analysis including DGP via
> Evalglare that should require a -vth or -vta view, so this is critical
> information for me.
> > May I ask why people refer to -vth as equi-solid angle and not
> hemispherical as it is defined in Radiance?s rpict man page?
> > My understanding from that page and from Axel Jacobs' presentation sent
> via the link just before is that there isn't a Radiance description for the
> equi-solid angle view.
> >
> > Best Regards
> >
> > Raquel Viula
> > PhD Researcher
> >
> > TU Delft | Faculty of Architecture and the Built Environment |
> > Architectural Engineering and Technology
> > Julianalaan 134, 2628 BL Delft, The Netherlands | P.O. Box 5043 2600 GA
> Delft
> >
> > From: Claus Br?ndgaard Madsen <[email protected]>
> > Reply-To: High Dynamic Range Imaging <[email protected]>
> > Date: Friday 27 January 2017 13:49
> > To: High Dynamic Range Imaging <[email protected]>
> > Subject: Re: [HDRI] Convert equisolidangular to equiangular projection
> >
> >
> >
> > Hi everyone,
> >
> > Some years ago I tested my Sigma 8mm lens, f3.5.
> >
> > At the time I found several sources online claiming it to be equi-solid
> angle (-vth), but it didn?t match my personal experiences with the lens, so
> I tested it.
> >
> > My tests showed it to be equidistant (-vta), i.e. identical to the
> angular fish eye projection in RADIANCE.
> >
> > So, in my experience, the 8mm Sigma lens is equidistant.
> >
> > Cheers,
> > Claus
> >
> >
> >
> > Claus B. Madsen
> > Assoc. Prof., Ph.D. | Department of Architecture and Media Technology
> >
> > Phone: +45 9940 8788 | E-mail: [email protected]
> > Aalborg University | Rendsburggade 14 | 9000 Aalborg | Denmark
> >
> > Employee No.: 107255 | Vat No.: DK29102384
> >
> >
> > From: "J. Alstan Jakubiec" <[email protected]>
> > Reply-To: High Dynamic Range Imaging <[email protected]>
> > Date: Friday, 27 January 2017 at 11.33
> > To: "[email protected]" <[email protected]>
> > Subject: Re: [HDRI] Convert equisolidangular to equiangular projection
> >
> > A little followup that is worth noting is that Axel Jacobs measured the
> Sigma 4.5mm and found it to have an equi-solid angle projection. See his
> presentation here: https://www.radiance-online.
> org/community/workshops/2012-copenhagen/Day2/Jacobs/Jacobs-
> AJ09-HDR_Radiance_WS-2012.pdf
> >
> > Alstan
> >
> >
> > On 1/27/2017 6:26 PM, J. Alstan Jakubiec wrote:
> > Hi Tobias,
> >
> > I just purchased a pair of Sigma 8mm f/3.5's for my work, but I haven't
> measured them for vignetting and angular verification yet. It is on my to
> do list :). I will be disappointed if they are equi-solid angular however.
> Will let you know sometime after the Lunar new year.
> >
> > Alstan
> >
> >
> > On 1/27/2017 6:17 PM, Tobias Porsch wrote:
> > Hi Alstan,
> >
> > I'm not sure if your below description is correct.
> > In my experience it's exactly the opposite. The Sigma f=8mm F/3.5 lens
> is an equi-solid angle (-vth) and the Sigma f=4.5mm F/2.8 is an
> equi-distant (-angular) (-vta) lens.
> > Can you please double-check that issue for me?
> >
> > Cheers
> > Tobias
> >
> > Von: J. Alstan Jakubiec [mailto:[email protected]]
> > Gesendet: Donnerstag, 26. Januar 2017 06:58
> > An: [email protected]
> > Betreff: Re: [HDRI] Convert equisolidangular to equiangular projection
> >
> > Hi Zhe,
> >
> > As far as I am aware, the Sigma 8mm f/3.5 is an equi-angular (-vta)
> lens, and the Sigma 4.5mm f/2.8 is an equi-solid angle (-???) lens. I am
> having trouble finding a source from Sigma right now, but Cauwerts, Bodart
> and Deneyer's paper says so.
> >
> > That said, if you do end up with an equi-solidangle image, I have a
> python script that converts equi-solid angle to equi-angle for each source
> jpeg while maintaining the EXIF data. I used this to convert
> equi-solidangle images from my Canon 8-15mm fisheye lenses.
> >
> > Best,
> > Alstan
> >
> > On 1/26/2017 8:48 AM, Gregory J. Ward wrote:
> > Hi Zhe,
> >
> > You should be able to apply the fisheye_corr.cal file I gave you earlier
> to correct the distortion and make it an angular fisheye image that pinterp
> works with.  (Why you need pinterp, I am not sure.)  The command is as
> suggested in the fisheye_corr.cal file itself:
> >
> >  pcomb -f fisheye_corr.cal -o fisheye.hdr \
> >         | getinfo -a "VIEW= -vta -vh 180 -vv 180" \
> >         > corrected.hdr
> >
> > This will also crop the area outside of 180? to black, assuming that is
> what you want.  It assumes that you have already cropped the image to a
> minimum square area.  You should apply vignetting correction and absolute
> calibration first.
> >
> > Cheers,
> > -Greg
> >
> > From: Zhe Kong <[email protected]>
> > Date: January 25, 2017 1:15:49 PM PST
> >
> > Dear list:
> > I am trying to compare HDR images and simulated luminance maps. Since I
> use SIGMA 8mm 1:3.5 for Canon, I need to convert equisolid-angular to
> equiangular project. I see very useful information from the post below:
> >
> > https://www.radiance-online.org:447/pipermail/radiance-
> general/2015-August/011184.html
> >
> > However, I still have some questions need to figure out.
> > 1) pinterp does not include equisolid-angular projection, so a equation
> needs to be applied to the function. Greg mentioned this simple expression,
> sin(theta)/theta, but I am still confused. Could anyone offer me the
> command?
> >
> > 2) The post discussed the steps of processing HDR images. If I get it
> right, the steps following "adjust exposure" are vignetting correction,
> adding view information, converting project from equisolidangular to
> equiangular, then calibrating the image. I use a GOSSEN Starlite 2 to
> record the luminance value on a grey card for calibration. My question is,
> should I calibrate the image before or after converting fisheye projection?
> >
> > Any suggestions or explanation would be appreciated.
> > Zhe
> >
> >
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-- 
*Zhe Kong*
*PhD Student*
*University of Wisconsin - Milwaukee *
*School of Architecture and Urban Planning *
*2131 E. Hartford Ave, Milwaukee, WI 53211 *
*Office 327*
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