On 17.9.2012 16:52, Ján Veselý wrote: > That is the point. If a function takes const type * as an argument, it > indicates that it does not modify the instance.
I hope I am not misguided, but I think this is simply not true when put like that. I believe it only indicates it will not modify the instance using _that_ const type * pointer, but does not indicate it will not modify it using another non-const pointers. This is also the reason behind my doubts about the first mail. Jakub _______________________________________________ HelenOS-devel mailing list [email protected] http://lists.modry.cz/cgi-bin/listinfo/helenos-devel
