All, I have an interesting filter problem (I think). I would like to remove duplicate filenames -- unfortunately, it is not quite as easy $ (sort ...).
I have 2 lists of files where one list has files with path prefixes and one doesn't. Some of these filenames (but not paths) are duplicated. I would like to combine the 2 into 1 list, with no duplicates of the filenames. My lists have hundreds of items each, but here is a simple example: LIST1 := file1.o file2.o file3.o LIST2 := path/file3.o path/file4.o path/file5.o Desired result of: LIST := file1.o file2.o file3.o path/file4.o path/file5.o I thought that this would do it: LIST3 = $(foreach xxx,$(LIST1),$(filter-out %$(xxx),$(LIST2))) LIST = $(LIST1) $(LIST3) but what that returns is a concatenated result for each loop (!?!): LIST = file1.o file2.o file3.o path/file3.o path/file4.o path/file5.o path/file3.o path/file4.o path/file5.o path/file4.o path/file5.o So "path/file3.o path/file4.o path/file5.o" appears twice (since file1.o and file2.o didnt filter out any values) then finally "path/ file4.o path/file5.o" (since file3.o filtered out path/file3.o). The solution would appear to somehow pass the output of the $(filter- out...) back in recursively. I am clueless as to do that... Many thanks for any help...
