On Thursday 22 April 2010 10:20:39 tuc wrote: > let A be a square matrix. then a eigenvector v to the eigenvalue a is > defined to have the property: > A*v=a*v. > > therefor for any real number x (nonzero, zero is never an eigenvector) > x*v is also a eigenvector of A: > A*(x*v)=x*(A*v)=x*(a*v)=a*(x*v) > > and since (-1) is a real number, mathematically speaking both results > are correct. >
ok :-) thanks in advance for the answer. Maybe i've understood. so it seems to be equal...but are symmetric and opposite values -0.735179 != 0.735179 but: abs( -0.735179 ) = abs( 0.735179 ) so :| i'm just think that if i use the value -1 for x and the value 1 the eigenvectors which i get are symmetric and opposite in sign no? :) _______________________________________________ Help-gsl mailing list [email protected] http://lists.gnu.org/mailman/listinfo/help-gsl
