On Thu, 2007-04-19 at 13:15 +0100, Dave Korn wrote:
> The obvious first approach - escape the comma so that filter-out doesn't
> think it's the separator between its two arguments - just doesn't work. I
> can't quite see how to achieve this in make....
Using backslashes as an escape character in make is pretty ad hoc; it
definitely does not work everywhere you expect it to (unfortunately).
However, you should be able to do it with variables:
COMMA = ,
LIST_WITHOUT_COMMAS:=$(filter-out $(COMMA),$(LIST_WITH_COMMAS))
--
-------------------------------------------------------------------------------
Paul D. Smith <[EMAIL PROTECTED]> Find some GNU make tips at:
http://www.gnu.org http://make.paulandlesley.org
"Please remain calm...I may be mad, but I am a professional." --Mad Scientist
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