Hi
I am running gnu make 4.1 on Ubuntu. Make builds my C++ application that
requires glibc 2.22 or higher. Ubuntu 14.04 has only glibc 2.19 so my makefile
checks the host o/s and, if it's Ubuntu, it links to my private copy of glibc
2.22:
GLIBC_FLAGS=
ifeq ($(DISTRO),debian)
echo "Warning: detected Ubuntu o/s so using different glibc to that
installed on this system"
GLIBC=$(MY_OPEN_SOURCE_LIBS)/glibc/v2_22/
GLIBC_FLAGS=
-Wl,-rpath=${GLIBC}:${GLIBC}/math:${GLIBC}/elf:${GLIBC}/dlfcn:${GLIBC}/nss:${GLIBC}/nis:${GLIBC}/rt:${GLIBC}/resolv:${GLIBC}/crypt:${GLIBC}/nptl\
-Wl,--dynamic-linker=${GLIBC}/elf/ld.so
endif
Now, Ubuntu 16.04 has glibc 2.23, so there I can use the standard glibc
packaged for the o/s. So I want to change the makefile code to only use my
private copy of glibc if glibc is <2.22.
I'm not sure whether it's best to detect the o/s version or the glibc version.
I can do the latter with:
~$ ldd --version
ldd (Ubuntu GLIBC 2.23-0ubuntu2) 2.23
Copyright (C) 2016 Free Software Foundation, Inc.
This is free software; see the source for copying conditions. There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
Written by Roland McGrath and Ulrich Drepper.
My question is, how can I extract the glibc version number from that ldd
response and use it in my makefile to only set GLIBC and GLIBC_FLAGS if the
glibc version is <2.22?
Best regards
David
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