No, it is not possible at present. See the Road Map for the planned new <join> feature, which will allow this kind of thing.
> hello, > > is it possible to define a joined subclass that has subclasses ? i have > tried, but i get a the following error: > > org.xml.sax.SAXParseException: Element "class" does not allow > "joined-subclass" here. > > here the structure: > > <class name="Transaction"> > > <id name="id"column="id" type="java.lang.Long" unsaved-value="null"> > <generator class="hilo"></generator> > </id> > > <discriminator column="transactionType" type="string"/> > > <property name="billedAmount" type="java.math.BigDecimal" > column="billedAmount" length="8" not-null="true"> > > <many-to-one name="order" class="Order" column="orderId" > not-null="true"/> > > <many-to-one name="payee" class="BusinessEntity" column="payee" > not-null="true"/> > > <many-to-one name="reciever" class="BusinessEntity" column="reciever" > not-null="true"/> > > <property name="transactionType" type="java.lang.String" > column="transactionType" length="10" not-null="true"/> > > > <subclass name="com.squirrel.model.order.CashTransaction" > discriminator-value="cash"> > > </subclass> > > > <subclass name="com.squirrel.model.order.ChequeTransaction" > discriminator-value="cheque"> > <property name="bank"type="java.lang.String" column="bank" > length="30"/> > </subclass> > > > <joined-subclass name="com.squirrel.model.order.CardTransaction"> > > <key column="id"/> > > <property name="approvalCode"type="java.lang.String" length="30" > /> > > <property name="cardHolderName" type="java.lang.String" > length="50" not-null="true"/> > > <property name="cardNumber" type="java.lang.String" length="30"/> > > <property name="cardType" type="java.lang.String" length="30"/> > > <property name="expireyDate" type="java.lang.String" length="5"/> > > </joined-subclass> > > > </class> > > I was also wondering if the feature could be added so that you could > define a descriminator value with a joined subclass. this would remove the > need for me to code this myself and provide the property in the class > definition. This would be useful as i am working with web developers who > are not using hibernate. > > thanks for any feedback > cam ------------------------------------------------------- This sf.net email is sponsored by:ThinkGeek Welcome to geek heaven. http://thinkgeek.com/sf _______________________________________________ hibernate-devel mailing list [EMAIL PROTECTED] https://lists.sourceforge.net/lists/listinfo/hibernate-devel
