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Ning Zhang commented on HIVE-741: --------------------------------- @Amareshwari, sorry the syntax was wrong for the 3 table joins. Below is the correct syntax and plan. {code} explain select * from src a left outer join src b on (a.value=b.value) right outer join src c on (b.value=c.value); OK ABSTRACT SYNTAX TREE: (TOK_QUERY (TOK_FROM (TOK_RIGHTOUTERJOIN (TOK_LEFTOUTERJOIN (TOK_TABREF src a) (TOK_TABREF src b) (= (. (TOK_TABLE_OR_COL a) value) (. (TOK_TABLE_OR_COL b) value))) (TOK_TABREF src c) (= (. (TOK_TABLE_OR_COL b) value) (. (TOK_TABLE_OR_COL c) value)))) (TOK_INSERT (TOK_DESTINATION (TOK_DIR TOK_TMP_FILE)) (TOK_SELECT (TOK_SELEXPR TOK_ALLCOLREF)))) STAGE DEPENDENCIES: Stage-1 is a root stage Stage-0 is a root stage STAGE PLANS: Stage: Stage-1 Map Reduce Alias -> Map Operator Tree: a TableScan alias: a Reduce Output Operator key expressions: expr: value type: string sort order: + Map-reduce partition columns: expr: value type: string tag: 0 value expressions: expr: key type: string expr: value type: string b TableScan alias: b Reduce Output Operator key expressions: expr: value type: string sort order: + Map-reduce partition columns: expr: value type: string tag: 1 value expressions: expr: key type: string expr: value type: string c TableScan alias: c Reduce Output Operator key expressions: expr: value type: string sort order: + Map-reduce partition columns: expr: value type: string tag: 2 value expressions: expr: key type: string expr: value type: string Reduce Operator Tree: Join Operator condition map: Left Outer Join0 to 1 Right Outer Join1 to 2 condition expressions: 0 {VALUE._col0} {VALUE._col1} 1 {VALUE._col0} {VALUE._col1} 2 {VALUE._col0} {VALUE._col1} handleSkewJoin: false outputColumnNames: _col0, _col1, _col4, _col5, _col8, _col9 Select Operator expressions: expr: _col0 type: string expr: _col1 type: string expr: _col4 type: string expr: _col5 type: string expr: _col8 type: string expr: _col9 type: string outputColumnNames: _col0, _col1, _col2, _col3, _col4, _col5 File Output Operator compressed: true GlobalTableId: 0 table: input format: org.apache.hadoop.mapred.TextInputFormat output format: org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat Stage: Stage-0 Fetch Operator limit: -1 {code} > NULL is not handled correctly in join > ------------------------------------- > > Key: HIVE-741 > URL: https://issues.apache.org/jira/browse/HIVE-741 > Project: Hadoop Hive > Issue Type: Bug > Reporter: Ning Zhang > Assignee: Amareshwari Sriramadasu > Attachments: patch-741.txt > > > With the following data in table input4_cb: > Key Value > ------ -------- > NULL 325 > 18 NULL > The following query: > {code} > select * from input4_cb a join input4_cb b on a.key = b.value; > {code} > returns the following result: > NULL 325 18 NULL > The correct result should be empty set. > When 'null' is replaced by '' it works. -- This message is automatically generated by JIRA. - You can reply to this email to add a comment to the issue online.