Compare the way the induction schema of arithmetic is represented
   by the single theorem num_INDUCTION. 

Thanks, Rob!  It's good to have a HOL Light example of an axiom schema.  

   (By the way I am assuming you are still working in HOL Light,
   though I don’t recognise some of the functions you are using, like
   NewAxiom).

Yes, I'm using the dialect of HOL Light defined by 
hol_light/RichterHilbertAxiomGeometry/readable.ml

   Note that that the stipulation that the formulas contain no free instances 
of a or b
   comes for free: the bound variables a and b will get renamed if necessary 
when
   you instantiate p and q.

Excellent! 

   This approach is the natural thing to do in HOL, but it typically
   gives something that is much stronger than the corresponding
   first-order schema. E.g., I expect you’d be able to use the axiom
   of continuity to construct the reals and prove they are complete,
   whereas I would expect Tarski’s axiomatic geometry to have a model
   based on algebraic reals that looks complete to first-order eyes,
   but can be seen not to be complete if you can quantify over
   arbitrary sets of points.

Yes, you're indeed correct, and 

   If, for some reason, you need the first-order restriction, then you
   have a lot more work to do: you would have to build a
   representation of the syntax of the first-order language and
   restrict the continuity axiom to properties that are expressed in
   that language.

Yes, that was the work I didn't know how to do.  Since the main point of 
Tarski's axioms is to get a ``model
   based on algebraic reals that looks complete to first-order eyes,'' it 
sounds like a bad idea to use your ``much stronger  axiom of continuity'' that 
gives us the reals.  Tarski's first order continuity axiom is strong enough 
because it specifies the real-closed fields, and then we can use Tarski's big 
theorem 
http://en.wikipedia.org/wiki/Real_closed_field
Alfred Tarski (1951) proved that [...] The theory of real closed fields is 
complete, o-minimal and decidable.

-- 
Best,
Bill 

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