On Wed, 2006-03-29 at 11:55 +0100, [EMAIL PROTECTED] wrote: > > > > Thanks for the attached Oleg - I've made these changes to the application, > but I'm still experiencing the same error; > > I/O exception (java.net.SocketException) caught when processing request: > Operation timed out: connect:could be due to invalid address > 2ab52ab5 HttpMethodDir I org.apache.commons.httpclient.HttpMethodDirector > Retrying request > > I've checked that the proxy server itself is OK by creating the connection > using Java.net.HttpURLConnection, and all appears to be OK. Do you have any > other suggestions as to where I may have gone wrong? > > Thanks, Greg >
Post a wire/context log of the HTTP session and relevant code snippets http://jakarta.apache.org/commons/httpclient/logging.html Oleg > > Oleg Kalnichevski <[EMAIL PROTECTED]> wrote on 29/03/2006 10:49:04: > > > On Wed, 2006-03-29 at 09:41 +0100, [EMAIL PROTECTED] wrote: > > > > > > > > > > > > I had a method which opens up http connections to URLs outside our > > > firewall, and in order to hide the implementation details of our > network, I > > > make the connection via a proxy server. I've previously used the > > > java.net.HttpURLConnection class, and specified a proxy by setting the > http > > > proxy settings (http.proxyHost/http.proxyPort/http.proxySet) as system > > > properties. The code to open the connection itself was fairly > > > straightforward ('url' in the snippet below is a java.net.URL object); > > > > > > > > > -------------------------------------------------------------------------------- > > > > > > > HttpURLConnection conn = (HttpURLConnection) url.openConnection(); > > > > > > > > > -------------------------------------------------------------------------------- > > > > > > > However...another application has deployed into the same JVM that my > > > application lives in, and due to co-existence issues (insert long story > > > here) I can no longer set these properties in the JVM. To try to just > set > > > the proxy on a connection-by-connection basis, I've changed my > application > > > code to try to use the HttpClient class to create the connection, and a > > > HostConfiguration object to set the proxy details; > > > > > > > > > -------------------------------------------------------------------------------- > > > > > > > HttpClient client = new HttpClient(); > > > PostMethod postMethod = new PostMethod(url.toString()); > > > > > > // ---- set various headers ---- > > > RequestEntity re = new StringRequestEntity(data); > > > postMethod.setRequestEntity(re); > > > HostConfiguration hostConfig = new HostConfiguration(); > > > > > > // the 'proxy' object holds the server name and port > > > hostConfig.setProxy(proxy.getProxyServer(), > proxy.getProxyPort()); > > > > > > > > > > > > client.setHostConfiguration(hostConfig); > > > > Do not do this. Pass the host configuration as a parameter to the > > HttpClient#executeMethod > > > > > > > > // do the send > > > int status = client.executeMethod(postMethod); > > > > > > > int status = client.executeMethod(hostConfig, postMethod); > > > > Hope this helps > > > > Oleg > > > > > > > > -------------------------------------------------------------------------------- > > > > > > > The proxy server/port are identical to the one I used before (when > using > > > HttpURLConnection, but I now get the following error from my server > code > > > when I tried to do the send; > > > > > > > > > > > > -------------------------------------------------------------------------------- > > > > > > > org.apache.commons.httpclient.HttpMethodDirector I/O exception > > > (java.net.SocketException) caught when processing request: > > > Operation timed out: connect:could be due to invalid address > > > org.apache.commons.httpclient.HttpMethodDirector Retrying request > > > > > > > > > -------------------------------------------------------------------------------- > > > > > > > > > > Any help much appreciated...... > > > > > > This e-mail is confidential, if you are not the intended recipient, do > not > > > retain/disclose it and please return it to us. 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