Hi Ortwin, I wanted to send the # character over the wire as it is. Is there a way that I can do it? Or can I set the fragment to the httpMethod?
Thnaks, Keith On 3/13/07, Ortwin Glück <[EMAIL PROTECTED]> wrote:
Keith, The # character is reserved to separate the fragment from the query/path. The fragment is not intended to be sent over the wire. So if you want to include such a character in an URI you should URL-escape it with %23: http://localhost:8081/axis2/services/ProbeDataService.RawParameterEndpoint/RawParameter%23id Does that work for you? Ortwin keith chapman wrote: > Hi, > > I want to send a http GET request to the followin url > > http://localhost:8081/axis2/services/ProbeDataService.RawParameterEndpoint/RawParameter#id > > > But i have to set a URI to the getMethod. > > I have the above as a URL. So I do the following > > getMethod.setURI(url.toString); > > This rips off the fragment part resulting in the following target URL > > http://localhost:8081/axis2/services/ProbeDataService.RawParameterEndpoint/RawParamete > > > How can I send a fragment in the url? > > Thanks, > Keith > -- [web] http://www.odi.ch/ [blog] http://www.odi.ch/weblog/ [pgp] key 0x81CF3416 finger print F2B1 B21F F056 D53E 5D79 A5AF 02BE 70F5 81CF 3416 --------------------------------------------------------------------- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
-- Keith Chapman WSO2 Inc. Oxygen for Web Services Developers. http://wso2.org/
