Hallöchen!

FabKzo writes:

> I'm not a dev, but does this mean that having a 29.42 mm instead
> of 28mm, for example, would be the result? So all calculus to find
> Hfov from there should be bad?

AFAIKS, everything is fine.  Hugin's calculations are precise.  The
only issue is that Hugin defines a focal length different from the
one that an optics textbook would define, that's all.

Tschö,
Torsten.

-- 
Torsten Bronger    Jabber ID: [email protected]
                                  or http://bronger-jmp.appspot.com

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