I think you are being modest. Is there a better explanation somewhere?

On Wednesday, 28 April 2021 at 08:18:24 UTC-4 bruno...@gmail.com wrote:

> It still doesn't feel like a particularly good explanation, I have
> trouble following it and I wrote it. I thought that maybe the mosaic
> mode in the preview overview could be modified to show all the camera
> positions in 3d, but then the panotools model allows multiple mosaic
> planes (with the plane yaw and plane pitch parameters, yes this is
> really hard to visualise), so I don't think this would make anything
> clearer, it would just add extra confusion.
>
> -- 
> Bruno
>
> On Mon, 26 Apr 2021 at 14:54, jmuc...@gmail.com <jmuc...@gmail.com> wrote:
> >
> > Just chiming in to note that an explainer like this would be lovely to 
> have in docs somewhere, if it isn't already.
> >
> > On Saturday, 17 April 2021 at 15:31:04 UTC-4 bruno...@gmail.com wrote:
> >>
> >> The distance from the TrX, TrY, TrZ = 0,0,0 position to the canvas
> >> plane is always 1. So if you lock the position of one of the photos
> >> to 0,0,0, you can ask the Hugin optimiser to try and find a position
> >> for the other photo that agrees with the control points in the
> >> project.
> >>
> >> In the Photos tab you need to select 'custom parameters', and
> >> optimise TrX and TrZ of the second photo (assuming that you have set
> >> the yaw for this to 48.9 and don't need to optimise it). If this
> >> results in a value for TrX of 0.1, given that this equates to 3.6"
> >> in real world units, then the distance from the first photo to the
> >> canvas plane is 3.6/0.1 = 36".
> >>
> >> Keep asking if this isn't working for you, this is a legitimate task
> >> for Hugin, but it isn't easy conceptually, it would be nice to have
> >> a good explanation, diagram or even some code that makes it easier.
>
> >> On Fri 16-Apr-2021 at 08:41 -0700, SRM wrote:
> >> >Hey Bruno,
> >> >I really appreciate your help on this. Unfortunately I am not finding
> >> >where Hugin will calculate the distance to the projection plane.
> >> >I am sorry I have to ask for your assistance again...but how/where do 
> I get
> >> >Hugin to calculate the distance to the anchor image projection plane.
> >>
> >> >On Friday, April 16, 2021 at 1:43:59 AM UTC-5 bruno...@gmail.com 
> wrote:
> >> >
> >> >> You divide the relative coordinates (in inches) by the distance (in
> >> >> inches) of the 'anchor' image from the projection plane - this gives 
> TrX
> >> >> etc. values which are unitless.
> >> >>
> >> >> If you don't know the distance to the projection plane, then Hugin 
> can
> >> >> calculate it for you. Estimate the distance and divide the 
> coordinates as
> >> >> above, then optimise just the TrZ values of all photos in the 
> project.
> >> >>
> >> >> On 15 April 2021 22:48:47 BST, SRM wrote:
> >> >> >It does make sense. I've been doing just that and am getting close 
> to what
> >> >> >I want to see, but I'd like to be a bit more precise with respect 
> to this
> >> >> >variable. Is there some way I can use the real word physical
> >> >> >measurements
> >> >> >I do know to calculate the correct offsets to apply to TrX and TrZ 
> for the
> >> >> >1unit sphere projection? Specifically I have a secondary camera 
> who's
> >> >> >entrance pupil was physically located at -3.6" in the TrX direction 
> and
> >> >> >
> >> >> >+1.6" in the TrZ direction with a Yaw of 48.9 relative to the 
> primary
> >> >> >camera who's corresponding location and yaw are zero. Isn't there 
> some sort
> >> >> >of formula I can apply to get an accurate TrX and TrZ value that 
> applies to
> >> >> >the 1 Unit Sphere? Perhaps the horizontal view angle of all the 
> cameras
> >> >> >(49.95 deg) would be a pertinent variable in such an equation?
>

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