I think so. The language grammar requires (if I read it
correctly) that the expr in an aexp of the form (op
expr) have a higher priority than op.
On Mon, 12 Mar 2001 [EMAIL PROTECTED] wrote:
> So why is (^2*3) not equvalent to \a->a^2*3 ?
Because it's being parsed as (^(2*3)) when it should be
rejected.
Jón
--
Jón Fairbairn [EMAIL PROTECTED]
31 Chalmers Road [EMAIL PROTECTED]
Cambridge CB1 3SZ +44 1223 570179 (pm only, please)
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