The point is: if IBM has not documented something, you cannot rely on it. It 
might be true for many years and can suddenly change with a new release. IBM 
can even legitimitely change the code you just checked how it works.

Kees.

"Thomas Berg" <thomas.b...@swedbank.se> wrote in message 
news:<e46b4df55a5e8746855078ae31f1b180336f71d...@fspas01ev010.fspa.myntet.se>...
> The point is: this is a very old interface, there could
> well be that it's always have the same content.  If You know
> the code behind You could verify that.
> 
> 
> 
> Regards,
> Thomas Berg
> __________________________________________
> Thomas Berg   Specialist   IT-U   SWEDBANK
> 
> 
> 
> 
> 
> > -----Ursprungligt meddelande-----
> > Från: IBM Mainframe Discussion List
> > [mailto:ibm-m...@bama.ua.edu] För Vernooij, CP - SPLXM
> > Skickat: den 29 oktober 2009 14:06
> > Till: IBM-MAIN@bama.ua.edu
> > Ämne: Re: A modest PARM proposal
> >
> >
> > The answer is: you don't know, so you can't and shouldn't
> > assume anything.
> > It is not an 0C4 'trap', you should not reference storage of
> > which you are not sure that you can reference it.
> >
> > Kees.
> >
> > "Thomas Berg" <thomas.b...@swedbank.se> wrote in message
> > news:<e46b4df55a5e8746855078ae31f1b180336f71d...@fspas01ev010.
> > fspa.myntet.se>...
> > > What is placed after the length field when it's zero ?
> > > A S0C4 trap ?  Or maybe some area which always is zero today ?
> > > (Hope never dies... :) )
> > >
> > >
> > >
> > > Regards,
> > > Thomas Berg
> > > __________________________________________
> > > Thomas Berg   Specialist   IT-U   SWEDBANK
> > >
> > >
> > >
> > >
> > >
> > > > -----Ursprungligt meddelande-----
> > > > Från: IBM Mainframe Discussion List [mailto:ibm-m...@bama.ua.edu]
> > > > För Vernooij, CP - SPLXM
> > > > Skickat: den 29 oktober 2009 13:29
> > > > Till: IBM-MAIN@bama.ua.edu
> > > > Ämne: Re: A modest PARM proposal
> > > >
> > > > No parm in JCL results in a parmfield with a lenghtfield of zeros.
> > > >
> > > > L     R3,0(R1)            ADDRESS OF PARM.
> > > > LH    R2,0(R3)            LENGTH OF PARM.
> > > > LTR   R2,R2               LENGTH ZERO?
> > > > BZ    END                 ==> NO PARM.
> > > >
> > > > Kees.
> > > >
> > > > "Thomas Berg" <thomas.b...@swedbank.se> wrote in message
> > > > news:<e46b4df55a5e8746855078ae31f1b180336f71d...@fspas01ev010.
> > > > fspa.myntet.se>...
> > > > > There is of course a problem if You have a program that:
> > > > > 1. Expects parm from both the JCL PARM mechanism and
> > from common
> > > > > standard linkage/calls,  and 2. Receives a parm with a length
> > > > > field value of exactly 100,  and 3. Can't determine if the parm
> > > > in reality
> > > > > is longer than that or not (that is: if coming from JCL).
> > > > >  and
> > > > > 4. The calling is not through JCL PARM,  and 5. The
> > calling part
> > > > > is not aware of this new possible format.
> > > > >
> > > > > The question is of course if this situation is a big problem in
> > > > > practice.  Someone with knowledge has to evaluate that.
> > > > >
> > > > >
> > > > > BTW, when You omit the JCL PARM, what does the program receive ?
> > > > > A length field with value zero only ?  What type of
> > area is placed
> > > > > immediately after the length field in this case ?
> > > > >
> > > > >
> > > > >
> > > > > Regards,
> > > > > Thomas Berg
> > > > > __________________________________________
> > > > > Thomas Berg   Specialist   IT-U   SWEDBANK
> > > > >
> > > > >
> > > > >
> > > > >
> > > > >
> > > > > > -----Ursprungligt meddelande-----
> > > > > > Från: IBM Mainframe Discussion List
> > > > > > [mailto:ibm-m...@bama.ua.edu] För Vernooij, CP - SPLXM
> > > > > > Skickat: den 29 oktober 2009 11:52
> > > > > > Till: IBM-MAIN@bama.ua.edu
> > > > > > Ämne: Re: A modest PARM proposal
> > > > > >
> > > > > > Don't think it is that simple.
> > > > > > I know how the parmfield works today.
> > > > > > If I understand the proposed new parmfield correctly,
> > > > > > > > > Today:    lengthfield + parm (max 100 bytes)
> > > > > > > > > Tomorrow: lengthfield + parm (max 100 bytes) +
> > > > padding to 102
> > > > > > the first 102 bytes will remain unchanged and additional
> > > > parms will
> > > > > > be appended to it. This means the first length field will
> > > > never be
> > > > > > more than 100.
> > > > > > How can a program determine if the data in bytes 101 and
> > > > further are
> > > > > > part of the new parmlayout and contain the lengthfield of the
> > > > > > remainder of the parm OR it is data not related to the
> > > > parm. In the
> > > > > > last case, referencing data after byte 100 can even
> > > > result in an 0C4
> > > > > > abend.
> > > > > >
> > > > > > Kees.
> > > > > >
> > > > > >
> > > > > > "Graeme Gibson" <gra...@ase.com.au> wrote in message
> > > > > > news:<20091029111112.3a5761c...@mail.ase.com.au>...
> > > > > > > >How can new programs determine if they received the new or
> > > > > > > >the old format, i.o.w. if they can/should process the data
> > > > > > > >after
> > > > > > byte 100 or
> > > > > > not?
> > > > > > >
> > > > > > > It's really quite simple Kees, the program should process
> > > > > > exactly the
> > > > > > > number of bytes that the 2-byte (halfword) length
> > > > prefix says is
> > > > > > > present, no more and no less.  This has been the case for >
> > > > > > 40 years.
> > > > > > >
> > > > > > > Running a program in batch that lets me dump storage:
> > > > > > >
> > > > > > > //STEP1   EXEC PGM=DBUG,PARM='TP,L,HC,PA=(ABCDEFGH)'
> > > > > > >
> > > > > > > here's what R1 -> at the time the program receives control:
> > > > > > >
> > > > > > > L R1$ 128      /* list what R1 points at for 128 bytes
> > > > > > > 00006FE0(+000) 80006FE6 00000015 E3D76BD3 6BC8C36B
> > > > > > |::?W::::TP,L,HC,|
> > > > > > > 00006FF0(+010) D7C17E4D C1C2C3C4 C5C6C7C8 5D000000
> > > > > > |PA=(ABCDEFGH):::|
> > > > > > > 00007000(+020) 00000000 00000000 00000000 00000000
> > > > > > |::::::::::::::::|
> > > > > > > 00007010(+030) 00000000 00000000 00000000 00000000
> > > > > > |::::::::::::::::|
> > > > > > >
> > > > > > > Breaking it up a bit to make it clearer:
> > > > > > >
> > > > > > > 006FE0  80006FE6      /* the parmlist (with end-of-list
> > > > bit ON) ->
> > > > > > > 006FE6  0015          /* the length prefix part of
> > the parameter
> > > > > > > 006FE8  E3D76BD3 6BC8C36B D7C17E4D C1C2C3C4 C5C6C7C8
> > > > 5D00   /* the
> > > > > > > string part in hex
> > > > > > >          T P , L  , H C ,  P A = (  A B C D  E F G H  )
> > > > > >  /* ..and
> > > > > > > in characters
> > > > > > >
> > > > > > > Now, there's NO padding out of the string buffer to 100
> > > > characters
> > > > > > > with blanks.  So, what are those "broken" programs making
> > > > > > of all those
> > > > > > > x'00' bytes that follow the actual PARM= value?  Countless
> > > > > > > existing programs may well be moving an arbitrary 100
> > > > or 102 bytes
> > > > > > of parameter
> > > > > > > to their own buffer/work area, but it seems clear that
> > > > those same
> > > > > > > programs must be taking notice of the length prefix when it
> > > > > > comes to
> > > > > > > parsing the string.  Or perhaps they all regard an x'00'
> > > > > > > as indicating end of PARM= string!  But then I'm not
> > > > aware of any
> > > > > > > commitment by IBM to ensure that the PARM= string is even
> > > > > > filled out
> > > > > > > with x'00' bytes.
> > > > > > >
> > > > > > > So, assuming the CI/SWA/Initiator support for PARM= was
> > > > enhanced
> > > > > > > to allow PARM= strings up to 32767 (x'7fff') characters.
> > > > > > Presumably the
> > > > > > > Initiator would continue, as it does now, to place the
> > > > > > PARM= parameter
> > > > > > > in a storage area big enough to hold the maximum size
> > > > it can be,
> > > > > > > ie
> > > > > > > 32767+2 bytes (instead of 102 bytes as at present).
> > > > Nothing would
> > > > > > > change for those existing (strictly
> > > > > > > "broken") programs that are copying an arbitrary 100 (or
> > > > > > 20, or some
> > > > > > > other number?) bytes of data into their own work areas.
> > > > > > >
> > > > > > > Of course, if a person using that program changed the PARM=
> > > > > > string to
> > > > > > > be longer than 100 characters, then all bets are off.
> > > > > > >
> > > > > > > The best outcome would be a message; like "I'm sorry
> > > > Dave, but I
> > > > > > > thought you knew that I can't handle a PARM string of more
> > > > > > > than 100 characters.  Report to the airlock immediately".
> > > > > > >
> > > > > > > An abend would be ok too.
> > > > > > >
> > > > > > > Just continuing to execute with possibly unknown results
> > > > > > would be the
> > > > > > > worst outcome.
> > > > > > >
> > > > > > > I suspect that there are programs in existence which
> > > > cannot accept
> > > > > > > even 20 characters of PARM= data, because the programmer
> > > > > > assumed there
> > > > > > > would only be, say, an 8 digit date (yyyymmdd), or some
> > > > > > other tiddly
> > > > > > > bit of data in the PARM= field.
> > > > > > >
> > > > > > >
> > > > > > > Ok, it's nearly Christmas / Hannuka / Pagan Pissup (ie.
> > > > > > drinking) time
> > > > > > > again, so take care all.
> > > > > > > Graeme.
> > > > > > >
> > > > > > >
> > > > > > > At 02:47 AM 29/10/2009, you wrote:
> > > > > > > >How can new programs determine if they received the new or
> > > > > > > >the old format, i.o.w. if they can/should process the data
> > > > > > > >after
> > > > > > byte 100 or
> > > > > > not?
> > > > > > > >
> > > > > > > >Kees.
> > > > > > > >
> > > > > > > >
> > > > > > > >"Thomas Berg" <thomas.b...@swedbank.se> wrote in message
> > > > > > > > > Today:    lengthfield + parm (max 100 bytes)
> > > > > > > > > Tomorrow: lengthfield + parm (max 100 bytes) +
> > > > padding to 102
> > > > > > > > bytes + newlengthfield + newparm (max 4GiB ? :) )
> > > > > > > > >
> > > > > > > > > This of course has the limitation means that
> > the receiving
> > > > > > > > > part
> > > > > > > > has to add 102 to get the long parm.
> > > > > > > > > But it will only affect new programs that need to
> > > > handle more
> > > > > > > > that 100 bytes parms, I think ?
> > > > > > >
> > > > > > >
> > > > > >
> > > >
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