May be there is a reason as to why you are gettign so many different answers.
In my case, the question I normally get from management is: how much is it 
going to cost us to maintain a copy our application XXX data at our DR location?
I change this into a problem of money and budgets.
I figured that the biggest variable cost is the network and the disk space.
The network also adds other traffic overheads depending on the protocols and 
recovery but it is highly unlikely that I will get a black and white estimate.
The good news about the network is that they sell bandwidth in big jumps so I 
estimated my worse case scenario by running so tests, made some assumptions 
(including my data compression), and added the next level of bandwidth (ended 
up with an OC-12).  I gave myself lots of head room because I found that 
sometimes the equipment doing the compression can fail.
The amount of disk was easy, whatever I had needed to be on the other side.
In other words, may be the problem that you are trying to solve needs to be 
revisited.  MB/sec is a moving target that can produce as many answers 
depending on the assumptions you make and who you ask.
Regards,
Uriel 

________________________________________
From: IBM Mainframe Discussion List [IBM-MAIN@bama.ua.edu] on behalf of Bill 
Fairchild [bfairch...@rocketsoftware.com]
Sent: Wednesday, March 21, 2012 10:03 AM
To: IBM-MAIN@bama.ua.edu
Subject: Re: megabytes per second

Everyone is missing the point.  Let me rephrase.
What do most users and managers think when they hear or use the phrase "copy 
data at xxx number of MB/sec.?"  Do they think that means the theoretically 
fastest possible rate at which data can be transferred under ideal conditions, 
or the actual rate at which that user's data can be transferred as that data 
exists at the instant when the copying is done?
Only scenario to consider:  an unsophisticated user runs a tool that tells him 
his data center's mission-critical, home-grown access method file Y has 10,000 
MB of data in it.  File Y, however, has been allocated to hold 20,000 MB of 
data.  Maybe their home-grown access method does not use DS1LSTAR properly.  
Maybe DS1LSTAR is maintained but a very inefficient block size is being used.  
Perhaps the tool reads every track and adds up the block size of all blocks in 
it.  Perhaps the tool looks at the RECFM, BLKSIZE, and device type and computes 
the size of the contents.  The point here is that there is really only 10,000 
MB of user data stored in this file that could theoretically hold twice as much 
data.  The backup process has been designed to copy every track in the file.  
Not knowing that each track in his file is only 50% full of data (inter-record 
gaps, inefficient block size, not enough data yet in the file to fill up each 
track completely, whatever), he runs a copy pro!
 duct that can copy 100MB/sec.  and finds that it takes 200 seconds to copy his 
10,000 MB of data stored in a 20,000 MB file.  He measures the elapsed time by 
looking at the start and end timestamp in his JES job log as any 
unsophisticated user would.  He wants to know why he is only getting 50MB/sec. 
of copy speed from his copy process that claims it can copy 100MB/sec from DASD 
to tape.
The worst case scenario is that the file is only allocated and has never been 
loaded with data.  In this case, the actual data transfer rate should be 0 
MB/secs., but it would still take 200 seconds to copy the file to tape.

Bill Fairchild

-----Original Message-----
From: IBM Mainframe Discussion List [mailto:IBM-MAIN@bama.ua.edu] On Behalf Of 
Ron Hawkins
Sent: Tuesday, March 20, 2012 8:59 PM
To: IBM-MAIN@bama.ua.edu
Subject: Re: megabytes per second

Bill,

It can also depend on where you are measuring the throughput:

        Back end of the disk array - there is additional data to transfer due 
to the encapsulation of EBCDIV within SCSI FBA blocks
        FICON - It's a 10 bit byte, so divide the data rate by 8 bits. A 1Gb 
channel is 1000MB/10=100 GB (yes no little i)
        Tape Drive - whatever you get after ICRC
        Virtual Tape Drive - whatever you get after ICRC and De duplication

This could be a fun topic.

Ron

> -----Original Message-----
> From: IBM Mainframe Discussion List [mailto:IBM-MAIN@bama.ua.edu] On
> Behalf Of Bill Fairchild
> Sent: Tuesday, March 20, 2012 3:12 PM
> To: IBM-MAIN@bama.ua.edu
> Subject: [IBM-MAIN] megabytes per second
>
> New thread.
>
> What exactly does "MB/second mean when referring to how much data can
> be copied from a DASD to a tape?
>
> To be more precise, I am not interested in big MB vs. little mib, just
> the philosophy.  Suppose I have a huge file on a "3390" virtual thing
> and I
can
> copy whole tracks to tape at the rate of 100 MB/sec.  Assume the
> tracks
hold
> 50,000 bytes instead of 56,664 to make the math easier.  Does 100 MB/sec.
> mean that I am copying 2,000 tracks per second?  Maybe.  What if there
> is nothing written on the tracks, but I don't know that until I read
> them in
and
> then write the contents?  Of course, there is always at least an R0 on
every
> track, so they are not completely empty.  If all they have written on
> them
is
> R0, am I still transferring data at the rate of 100MB/sec?  If each
> track
were
> half full, would my effective data transfer rate be only 50 MB/sec?
>
> Bill Fairchild
>
> -----Original Message-----
> From: IBM Mainframe Discussion List [mailto:IBM-MAIN@bama.ua.edu] On
> Behalf Of Alan Altmark
> Sent: Monday, March 19, 2012 5:39 PM
> To: IBM-MAIN@bama.ua.edu
> Subject: Re: host codepge 0037 and the obscure "not sign"
>
> On Tue, 13 Mar 2012 12:51:26 -0400, Shmuel Metz (Seymour J.)
> <shmuel+ibm-m...@patriot.net> wrote:
> >>Is there any translation table in z/os 1.11 that translates the "NOT
> >>SIGN" x'5F' to an ascii x'AC',
> >
> >These is no ASCII 'AC'X; you really need to know what code pages
> >you're using to get a correct translation.
>
> If you use UCS-2, the NOT SIGN is U+00AC.  But you're right, it isn't
ASCII, it's
> Unicode.
>
> TYPE U 2 B  (big endian Unicode)
> TYPE U 2 L   (little endian Unicode)
>
> Also look at SITE UCSHOSTCS.
>
> Alan Altmark
> IBM
>
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