And "stores integers in big-endian form" is not unconditionally true. There are 
the LOAD REVERSED and STORE REVERSED instructions which load and store, 
respectively, the bytes in the register specified into the memory location 
specified in reverse sequence. I.e. bytes 0..3 or 0..7 load or store into bytes 
3..0 or 7..0 of the specified memory location. Of course, integers in registers 
do need to be in big-endian format in order to be used for arithmetic 
operations (at least if you want the correct result).

-- 
John McKown
Systems Engineer IV
IT

Administrative Services Group

HealthMarkets®

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> -----Original Message-----
> From: IBM Mainframe Discussion List [mailto:IBM-MAIN@LISTSERV.UA.EDU]
> On Behalf Of Charles Mills
> Sent: Tuesday, September 04, 2012 9:57 AM
> To: IBM-MAIN@LISTSERV.UA.EDU
> Subject: Re: The IBM zEnterprise EC12 announcment
> 
> Just because you *can* create a malformed string with no delimiter does
> not mean that my statement about proper C behavior is untrue.
> 
> It is a true statement that "the z architecture stores integers in big-
> endian form." Nonetheless, I *can* create a little-endian integer on z.
> That does not make the statement untrue.
> 
> BTW, C++ gives an error for the s6[6] = "wombat" case.
> 
> Charles
> 


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