Martin, Pretty sure this only works with Metal C. Inline assembly code requires the GENASM compiler option which is only valid in combination with the METAL option. Otherwise __asm is ignored. Personally, I think that is a bad design, it should not be simply ignored but would at least generate a warning.
http://publibz.boulder.ibm.com/cgi-bin/bookmgr_OS390/BOOKS/cbclr1b0/7.8 http://publibz.boulder.ibm.com/cgi-bin/bookmgr_OS390/BOOKS/CBCUG1A0/4.53 See the end of this post for instructions on using the ibm-mail list server list. You'll get better response since only a few folks may be using the google mirror of the postings. Cheers. -- forwarded post -- Dear all, I try to test using a __asm statement in my C++ program. I simply like to add to values (x and y) and print this output. But it will not do so. x and y is alway the same. --- begin of code --- // test_inline.C #include <sstream> #include <iostream> #include <fstream> using namespace std; // MAIN int main(int argc, char *argv[]) { int rc=0; int x=9; int y=7; printf("%s %s\nBEFOR: x=%d y=%d\n",__DATE__,__TIME__,x,y); __asm ( "AR %0,%1\n" : "=r"(x) : "r"(y),"0"(x) ); // output, input, register define - none here done by compiler printf("AFTER: x=%d y=%d\n",x,y); exit(rc); } --- end of code --- Make: c++ -o test_inline -g -Wc,xplink -Wl,xplink test_inline.C Now if I run this in the USS the output is as following >./test_inline May 1 2014 09:25:31 BEFOR: x=9 y=7 AFTER: x=9 y=7 > does anybody can give me a hint whats wrong here ? Best Regards, Martin ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN
