It could also be done by taking advantage of the fact that adjacent string
literals are combined during compilation:
#define debug(a) printf("the value of " #a "is %d\n", a)
> -----Original Message-----
> From: IBM Mainframe Discussion List [mailto:IBM-MAIN@LISTSERV.UA.EDU] On
> Behalf Of Charles Mills
> Sent: Friday, September 05, 2014 7:00 AM
> To: IBM-MAIN@LISTSERV.UA.EDU
> Subject: Re: IBM C compiler substituting for macros inside literals?
>
> Not sure if your question is intended to be serious but on an ANSI C
> compiler there is no way to do substitution inside a literal string.
> However, what could have been accomplished with this:
>
> #define debug(a) printf("the value of a is %d\n", a)
>
> that is, a macro that would print "the value of foo is 27"
>
> can be accomplished with ANSI "stringification":
>
> #define debug(a) printf("the value of %s is %d\n", #a, a)
>
> The preprocessor turns #a into "foo" (including the quotes)
>
> Charles
> -----Original Message-----
> From: IBM Mainframe Discussion List [mailto:IBM-MAIN@LISTSERV.UA.EDU] On
> Behalf Of Martin Packer
> Sent: Friday, September 05, 2014 1:57 AM
> To: IBM-MAIN@LISTSERV.UA.EDU
> Subject: Re: IBM C compiler substituting for macros inside literals?
>
> So tell me, if one wanted to achieve this apparently non-standard effect
how
> WOULD one go about it?
>
> Not that I want to but it HAD to be asked. :-)
>
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