Charles,

We are running z/PDT , we should talk my friend, i think thats a good
question, i know you can emulate different architectures.

Scott

On Sat, Nov 28, 2015 at 12:17 PM, Charles Mills <charl...@mcn.org> wrote:

> I am trying to come up with a complete mapping of 4-digit machine types to
> C/C++ ARCH levels. (The universe for my "complete" is z architecture.)
>
>
>
> I am in pretty good shape for z900 through z13.
>
>
>
> I am dealing with future machines by assuming that anything not in my table
> is of an architecture level higher than those I know about. For my
> application this is a safe assumption. (I can failsafe in that direction; I
> do not want to fail in the other direction: report that the hardware is
> down-level when in fact it is not.)
>
>
>
> Google tells me that the zPDT is machine type 1090 or 1091. Is there a
> correlation to architecture level? I kind of get the feeling that IBM ships
> a software update from time to time that updates the instruction set to
> *some* level. Is there a way to determine the  architecture level of a zPDT
> instance other than by testing feature bits in the CVT? How does one set
> the
> C or COBOL ARCH level if one is targeting zPDT?
>
>
>
> FSI boxes are 390 only, right? Outside of the z universe?
>
>
>
> VM does not generally alter the problem instruction set of a guest, right,
> nor change the machine type number? (I recall that one can change the
> serial
> number.) If VM is running on a z196, every guest sees a machine type of
> 2817, correct? VM neither adds store on condition to a machine that does
> not
> support it at the hardware level, nor deletes it from a machine that does?
>
>
>
> I know that z/OS is not licensed on Hercules but hypothetically if someone
> were to run z/OS on Hercules, the machine type reported and the instruction
> set are consistent - is that correct? If someone is running Hercules in for
> example "z10 mode" then the machine type reported will be 2097/8 and
> decimal
> floating point will be present but load on condition will not?
>
>
>
> Charles
>
>
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