Sure. Less cup and much more manual work when a subroutine is updated...

ITschak

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‫ב-1 ביוני 2016, בשעה 19:44, ‏‏Mike Schwab ‏<mike.a.sch...@gmail.com> כתב/ה:‬

> Increase in size would indicate small subroutines converted to
> instream code.  Branches are expensive, so more core means faster /
> less CPU programs, at expense of more memory / I/O.
> 
>> On Wed, Jun 1, 2016 at 11:40 AM, Paul Strauss <strau...@us.ibm.com> wrote:
>> My customer wants to start the migration to Enterprise COBOL V5.2. I know
>> V6.1 is out but we need to get going on this project. I have deleted all
>> COBOL compilers below Enterprise COBOL V4.2 from their systems. I worked
>> with an applications representative and they have decided on the compiler
>> options they want. Load library conversion to PDSE is complete. Analysis
>> of load libraries looking for OS/VS COBOL and determining which of those
>> load modules are still in use has been determined and they will be
>> recompiled either with Enterprise COBOL V4.2 or V5.2. I know there are
>> some others things to look at but these are done.
>> 
>> If there is a COBOL specific web site for these types of questions that
>> would be a better place for these questions please let me know.
>> 
>> Some users have been playing with the new compiler and comparing it with
>> Enterprise COBOL V4.2. They have picked a few current programs and
>> compiled, linked and run them. One load module was 3-4 times as big when
>> compiled with OPT(2). With OPT(0) it was  %50 larger. Is this a typical
>> increase in size for V5.2 compiles?
>> 
>> Has anyone noticed a difference in CPU execution time either way?
>> 
>> A size increase would not be a big problem but a large increase in CPU
>> time would be.
>> 
>> Thank You,
>> 
>> Paul Strauss
>> 
>> IBM Global Services
>> z/OS MVS and Program Products
>> Department F2VE
>> 150 Kettletown Rd.
>> Southbury, CT 06488
>> (203) 272-2758
>> strau...@us.ibm.com
>> 
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> 
> 
> -- 
> Mike A Schwab, Springfield IL USA
> Where do Forest Rangers go to get away from it all?
> 
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