The gawk or awk (either one should work here) script utility could do it:
awk -e '{ print " " substr($0, 7) }' < input.file > output.file
Note single quotes (apostrophes) surrounding the script, double quotes within
for the 6 blanks.
HTH
Peter
-----Original Message-----
From: IBM Mainframe Discussion List [mailto:IBM-MAIN@LISTSERV.UA.EDU] On Behalf
Of Frank Swarbrick
Sent: Wednesday, October 11, 2017 1:23 PM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: git, z/OS and COBOL
This looks interesting. Do you know of a UNIX utility that would replace the
first 6 characters with spaces?
________________________________
From: IBM Mainframe Discussion List <IBM-MAIN@LISTSERV.UA.EDU> on behalf of
Jerry Callen <jcal...@narsil.org>
Sent: Wednesday, October 11, 2017 11:14 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: git, z/OS and COBOL
Regarding line numbering: git has the ability to run complementary "clean" and
"smudge" filters to be used when moving source between the repo and the working
directory; these might prove useful. See
https://git-scm.com/book/en/v2/Customizing-Git-Git-Attributes for more
information.
That said - I agree that if you CAN move away from line numbering, you SHOULD.
(Shameless plug...) BTW, if anyone has git questions specific to the z/OS port
of git from Rocket, please ask them on Rocket's open source forum at
https://forum.rocketsoftware.com/c/rocket-z-os-open-source-languages-tools. I
(and other Rocket employees) monitor it regularly.
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