Try this logic:
- Get the Julian date of today (YYXXX)
- Deduct 1 from Julian date (xxx)
- Last 3 digits zero? (xxx)
- Deduct one from first two chars (year) (YY)
- Decide the Julian date (365 or 366 based on year/4) (xxx)
ITschak
On Thu, Aug 2, 2018 at 10:38 AM saurabh khandelwal <
sourabhkhandelwal...@gmail.com> wrote:
> Hello Group,
>
> In REXX , we have Date function to calculate today's date but do we have
> any separate function to calculate yesterday's date.
>
> currently, we used
>
> TODAY= DATE('S')
> YESTERDAY = TODAY - 1
>
> this code work whole month but, starting of the month where we have date
>
> ex :
>
> TODAY - '20180801'
>
> then yesterday will be calculated like
>
> TODAY -1 , So yesterday value will be
> YESTERDAY = '20180800' , which is wrong.
>
> Can you please help to overcome this issue.
>
> ----------------------------------------------------------------------
> For IBM-MAIN subscribe / signoff / archive access instructions,
> send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN
>
--
ITschak Mugzach
*|** IronSphere Platform* *|* *Information Security Contiguous Monitoring
for Legacy **| *
----------------------------------------------------------------------
For IBM-MAIN subscribe / signoff / archive access instructions,
send email to lists...@listserv.ua.edu with the message: INFO IBM-MAIN
