It is 14% of the whole system, thus 40% of 499. But, CP is not scheduling a virtual machine, but virtual processors, and each virtual processor gets its own share. These virtual processors compete against each other to get CPU cycles. So, your guest with 14% Abs limit hard with: - if it has 1 processor, that has 14% share - give it 3, and each one gets at most 4.6% with the last case: if the guest has a process requiring 10% of the CPU, it will be hard to get it.
Note: with z/VM 5.4 CP will not count defined but inactive virtual processors when distribution the share given to the virtual machine over its virtual processors. 2009/5/5 Wandschneider, Scott <scott.wandschnei...@infocrossing.com> > > All, > > We have a 2066 with 3 CPs for a total of 499 MIPS. Given a guest operating > system with a share setting of 14% limit hard, does that equate to 14% of 499 > MIPS or 14% of 166 MIPS (one processor)? And then does defining a second or > third virtual CP change the percent of MIPS? > > Thank you, > Scott R Wandschneider > Senior Systems Programmer|| Infocrossing, a Wipro Company || 11707 Miracle > Hills Drive, Omaha, NE, 68154-4457|| �u: 402.963.8905 || �|:847.849.7223 || > : scott.wandschnei...@infocrossing.com **Think Green - Please print > responsibly** > > > Confidentiality Note: This e-mail, including any attachment to it, may > contain material that is confidential, proprietary, privileged and/or > "Protected Health Information," within the meaning of the regulations under > the Health Insurance Portability & Accountability Act as amended. If it is > not clear that you are the intended recipient, you are hereby notified that > you have received this transmittal in error, and any review, dissemination, > distribution or copying of this e-mail, including any attachment to it, is > strictly prohibited. If you have received this e-mail in error, please > immediately return it to the sender and delete it from your system. Thank you. -- Kris Buelens, IBM Belgium, VM customer support
