On Sat, Feb 22, 2014 at 1:20 AM, Salvatore Palomino
<[email protected]>wrote:

> Because the purpose of the function is to convert g into and undirected
> graph.
>

And it does just that.


> Also, when I use other functions that perform operations on graphs, they
> always return the graph. Thus, its logical that it would return g and not
> None.
>

No, they don't. They modify the graph in place and return None. E.g.:

>>> g=igraph.Graph()
>>> a=g.add_vertices(3)
>>> print a
None
>>> b=g.add_edges([(0,1), (1,2)])
>>> print b
None

Gabor


>
>
>
>
> On Fri, Feb 21, 2014 at 5:15 PM, Gábor Csárdi <[email protected]>wrote:
>
>> On Fri, Feb 21, 2014 at 8:10 PM, Salvatore Palomino <
>> [email protected]> wrote:
>>
>>> i think it should return g as an undirected graph. Instead it returns
>>> "None"
>>>
>>
>> Why should it return the graph?
>>
>> Gabor
>>
>>
>>>
>>>
>>> On Fri, Feb 21, 2014 at 4:07 PM, Gábor Csárdi <[email protected]>wrote:
>>>
>>>> On Fri, Feb 21, 2014 at 6:55 PM, Salvatore Palomino <
>>>> [email protected]> wrote:
>>>>
>>>>> Hello!
>>>>>
>>>>> I am trying to convert my directed graph g into an undirected graph
>>>>> using to_undirected().
>>>>>
>>>>> << g =
>>>>> GraphBase.Read_Pajek("C:/Users/Palomino/Downloads/109Senate-Rows.net")
>>>>> << g = g.to_undirected(False)
>>>>> << print g
>>>>> None
>>>>>
>>>>> I don't know why it returns None. Can you help me out?
>>>>>
>>>>
>>>> What should it return? The result of the conversion is in g, it does it
>>>> in place.
>>>>
>>>> G.
>>>>
>>>>
>>>>
>>>>>
>>>>> Thanks!!!
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
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>>>>>
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