You do realise a list-sort will not work with a procedure returning a constant value?
IOW if (comparer A B) => #t, then (comparer B A) => #f On Thu, May 21, 2009 at 8:23 AM, Ramana Kumar <[email protected]>wrote: > Can you help me think of situations in which replacing (lambda () > (null? '())) by (lambda () #t) produces different behavior in a > program? lambda, quote, and null? are from (rnrs) and the change is > occurring in the procedure passed to list-sort. I would rather not > post my complete program just yet because it's quite long, and I want > to pinpoint the exact issue... but let me know if there are pertinent > details I can supply. > -- http://codeplex.com/IronScheme http://xacc.wordpress.com
