[email protected] wrote:
> On 09-08-16 07:08 PM, David-Sarah Hopwood wrote:
>> [email protected] wrote:
>>> I looked at ANTLRStringStreams consume() method and noticed that it
>>> checks for a '\n'. In the current grammar I'm skip()ing newlines,
>>> instead of placing them on a hidden channel.
>>>
>>> I made the following modification to the grammar in ANTLRWorks which
>>> promptly broke the compiler.
>>> fragment NEWLINE : '\n' '\r'? {$channel=HIDDEN;};
>>> fragment WS : ('\n'|'\r'|'\t'|' ')+ {$channel=HIDDEN;};
>>>
>>> The error message is "cannot find symbol : variable _channel".
>> That's quite strange; I'm using $channel = HIDDEN in ANTLRWorks (version
>> 1.2.3) with no problems. Could something be wrong with your ANTLR/ANTLRWorks
>> installation?
>>
>> Can you reduce the grammar to the minimum necessary to reproduce the above
>> error message, and post it here?
>
> I tested on ANTLRWorks 1.2.3 also and the same error occurs. I don't
> think there's anything wrong with my ANTLRWorks installation? java -jar
> antlrworks-1.2.3.jar
>
> grammar bug;
> bug : EOF;
> fragment NEWLINE : '\n' '\r'? {$channel=HIDDEN;};
>
> Console:
> [19:14:16] /output/bugLexer.java:50: cannot find symbol
> [19:14:16] symbol : variable _channel
> [19:14:16] location: class bugLexer
> [19:14:16] _channel=HIDDEN;
> [19:14:16] ^
> [19:14:16] 1 error
OK, I can reproduce that using
java org.antlr.Tool bug.g
javac bug*.java
so we can eliminate ANTLRWorks.
The generated code for mNEWLINE does not contain
int _channel = DEFAULT_TOKEN_CHANNEL;
...
state.channel = _channel;
as I would expect it to. Someone with a deeper knowledge of ANTLR internals
will have to investigate why not.
--
David-Sarah Hopwood ⚥ http://davidsarah.livejournal.com
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